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Old 28.06.2006, 08:29   #1
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Default АЛГЕБРА. МАТ.АНАЛИЗ. ГЕОМЕТРИЯ

АЛГЕБРА. МАТ.АНАЛИЗ. ГЕОМЕТРИЯ
there you have the Linke brothers:
http://ihtik.lib.ru/math_1june2006/
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Old 28.06.2006, 08:34   #2
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Default Re: АЛГЕБРА. МАТ.АНАЛИЗ. ГЕОМЕТРИЯ

that's many books
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Old 28.06.2006, 10:35   #3
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So Thanxxxxxxxxxx men
& Nice to meet U
can U help!?
I need this Book:
Techniques in fractal Geometry "Kenneth Falconer", 1997
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Old 28.06.2006, 11:15   #4
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thanks? for what? i just quoted Slayers_`Boxer`
and nice to meet you too
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Old 17.11.2006, 00:36   #5
Im blond whats ur excuse?
 
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Dorogie forumchane, ya konechno znayu chto vy zdes' seryoznym delom zanimaytes', no vsyo zhe nuzhna vasha pomosh'

Vot u menya takaya trivial'naya problema, no ne mogu re****', vernee reshayu no otvet poluchennyj mnoyu ne sootvetstvuet.

Vochinch che, vor angghierena

Tak vot.

a)Find the equation of the straight line passing through the points with coordinates (-1;5) and(4;-2) giving ur answer in the form ax+by+c=0, where a, b, c are integers.
The line crosses the x axis at the point A and the y axis at the point B, and O is the origin
b)Find the area of triangle(simbol ) OAB

Mers u in advance
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Regardz Megardz

Last edited by Meme; 17.11.2006 at 09:31.
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Old 17.11.2006, 00:45   #6
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I'll write here how I have worked out the problem, so far for u not to think I am lazy

First of all I've found the equation of the line, which is 7x+5y-18=0
Afta, the coordinates of A (18/7;0) B(0;18/5) and O (0;0)(karogha stegh mi ban en chem arel, bayc it says O, is the origin). I have also found all the sides of the triangle OA=0 AB=-1 BO=18/5 no ploshad' kak vidite, ne poluchaetsya, a ona est' ):
A=1/2hxbase

Last edited by Meme; 17.11.2006 at 09:17.
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Old 17.11.2006, 01:41   #7
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длина АВ не может быть отрицательной. ОА не равно нулю. ОА = 18/7.
площадь прямоугольного треугольника = 1/2 * (ОА)*(ОВ)
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Old 17.11.2006, 11:42   #8
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Da teoreticheski eto ne vozmozhno.
Lara a kak vy poluchili dlina OA=18/7?
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Old 17.11.2006, 12:07   #9
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можно по формуле: расстояние между двумя точками с заданными координатами равно корню квадратному из суммы квадратов разницы координат.
но в этом случае это очевидно - ведь т.О - начало координат.
вы, чтоб не путаться, постройте эту прямую и все станет ясно.
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Old 25.12.2006, 18:51   #10
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zhzhet
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mathsolver.jpg  
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Old 07.02.2007, 23:04   #11
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Nastoyashaya golovolomka, ili zhe noch'yu u menya tormozhenie mozga (esli takova imeecca vashe )


Two cars A and B are moving on straight horizontal roads with constant velocities. The velocity of A is 15m/s due east and the velocity of B is 20 (i-j)m/s, where i and j are unit vectors directed due east and due north respectively. When t=0 A is at the origin O and the position vector of B relative to O is 200j m. At time t seconds, the position vectors of A and B are r and s.

(a) Find the time when B is due east of A.
(d) Find the time when the cars are again 200m apart.

HELP!
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Old 08.02.2007, 21:23   #12
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Lareeeeg, a Lareg, nu gde zhe ty a?
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