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Дошкольник Join Date: 04 2003 Location: USA
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Guys i have a question about comparing strings.For example string word1; string word2; word1="Tremendous"; word2="Tremble"; word1<word2; The boolean value will be false , cause computer compares each character one by one and as "b" has lesser value in ASCII than "e", it gives a false value. So the question is , can computer stop at the first character in the string, meaning that it will compare just "T" and set the boolean value to true?
__________________ No se preocupe, sea feliz ! Last edited by Diane-; 11.06.2003 at 17:37. |
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Грустно... Join Date: 08 2002 Location: Там, где всегда идут дожди Age: 38
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1. the value 'b' is less than the value 'e' ![]() 2. If computer stops after the first symbol the result will be false , because 'T' < 'T' is false ('T' <= 'T' is true). Лучше скажите нам, что вам нужно... ![]() ![]() |
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![]() | #3 |
Banned Join Date: 10 2002 Location: Brooklyn, New York Age: 42
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1. dobav'te proverochku na dlinnu stroki (smotrya chto vam nujno... esli ugodno schitaite dlinnuiu stroku bol'shei) 2. v ostal'nix sluchayax vse pral'no. (esli dlinna ravna) 3. chestno govorya ya ne ochen' ponyal vopros.... |
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Дошкольник Join Date: 04 2003 Location: USA
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Reputation: 0 | 0 | ![]() ![]() And I know that "T"<"T" will be false, thats not what i was asking. Nam nichego ne nujno ,nujen bil otvet na etot vopros, vozmojno li ostanovit posle pervoi bukvi. Danyer ,"dobavit proverochki" kak na angliyskom budet zvuchat? ![]() Eto ne svyazano s kakim to imenno projectom i ya znayu chto etot privedennii mnoyu primer veren. vopros lij v tom, mojli li ostanovit computer posle pervoi bukvi, v lubom sravnenii string-ov. Neznayu kak vam eshe obyasnit ![]() |
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![]() | #6 |
Banned Join Date: 10 2002 Location: Brooklyn, New York Age: 42
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mojno. 1. proveryai TOL'KO pervuiu bukvu (if(s1[0]==s2[0])) 2. s[i] i nachinai s 0 ne narashivai. chto to je samoe chto i s1[0] ---------- add a condition checking e.g. if ( strlen(s1) > strlen(s2)) i t.d. biblioteka string.h |
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