30.09.2001, 05:38 |
#1 |

Академик Join Date: 09 2001 Location: inside myself
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Hi.<BR>64-bit encryption means that u're using 64 but for an item, say for a word (or term, or whatever). It's also called "vector". The length of vector predetermines the "hardness" of decripting, just like with 20 words you will create much more sentences than with 3 words. Cracking in some cases is just enumeration (linear or more "intellectual") of possible values vot particular "vector" - based on statistical params like deviation, frequency, probability, etc. And that's why longer chipher means longer time for enumeration. 64 power of 2 gives you a huge amount of variations.<BR> <IMG SRC="smile.gif" border="0"> Hope this will help.<BR>What related to the sample you gave - it' too hard for me to understand.. <IMG SRC="smile.gif" border="0">
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30.09.2001, 08:04 |
#2 |

Младенец Join Date: 09 2001
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This is my first question (there will be more...). If I create a 64 bit encryption alghoritms it means that I: Char --> Decimal<BR>Decimal --> Binary adding the binary 8-bit blocks<BR>and separate them into 6-bit blocks. 6bit --> Decimal<BR>Decimal --> Char right? I dont get it, why is this 64-bit encryption?<BR>sure the max value of a block with 6bits is 111111 = 64 but still... then 256 bits encryptions should be 8bit blocks wich is the original value...or am I completly wrong? And why is 256 bit the best encryptions, how come a 8bit block results in better security than a 6 bit block? does it take longer time to bruteforce? Please enlighten me.
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27.10.2001, 04:40 |
#3 |

Младенец Join Date: 10 2001 Location: Wisconsin
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What you have described is not encryption but COMPRESSION. When you encrypt, you take the original string as 1 big number, then "encrypt" the big number with another number, usu. a prime number. that way, do "decrypt" it back again, you must supply the prime number used. Make sense? <BLOCKQUOTE><font size="1" face="Verdana, Helvetica, sans-serif">quote:</font><HR>Originally posted by d_l0rd:<BR> This is my first question (there will be more...).<HR></BLOCKQUOTE>
If I create a 64 bit encryption alghoritms it means that I: Char --> Decimal<BR>Decimal --> Binary adding the binary 8-bit blocks<BR>and separate them into 6-bit blocks. 6bit --> Decimal<BR>Decimal --> Char right? I dont get it, why is this 64-bit encryption?<BR>sure the max value of a block with 6bits is 111111 = 64 but still... then 256 bits encryptions should be 8bit blocks wich is the original value...or am I completly wrong? And why is 256 bit the best encryptions, how come a 8bit block results in better security than a 6 bit block? does it take longer time to bruteforce? Please enlighten me. |

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